does assignment operator work with different types of objects?

class A {
public:
void operator=(const B &in);
private:
 int a;
};

class B {
private:
 int c;

}

sorry. there happened an error. is assignment operator valid ? or is there any way to achieve this? [There is no relation between A and B class.]

void A::operator=(const B& in) 
{ 
a = in.c;

}

Thanks a lot.

From stackoverflow

• Yes you can do so.

  #include <iostream>
  using namespace std;
  
  class B {
    public:
      B() : y(1) {}
      int getY() const { return y; }
    private:
       int y;
  };
  
  
  class A {
    public:
      A() : x(0) {}
      void operator=(const B &in) {
         x = in.getY();
      }
      void display() { cout << x << endl; }
    private:
       int x;
  };
  
  
  int main() {
     A a;
     B b;
     a = b;
     a.display();
  }
  

  Naveen : You can also make getY() as a const member function and avoid the const_cast.

  Dave Van den Eynde : Yes, make getY const, and don't cast constness away.

  Shree : True... was just lazy to go back and change it :)

  David Rodríguez - dribeas : Or else make A a friend of B so that it can access private elements.

• Both assignment operator and parameterized constructors can have parameters of any type and use these parameters' values any way they want to initialize the object.